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By Dr Antonio Gulli

Programming interviews in C++ approximately timber

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The total is still keys. The number of branches from a node is one more than the number of keys stored in that node. A B-tree is kept balanced by requiring that all leaf-nodes are at the same depth. More formally a B-tree of order is defined as a tree which satisfies the following properties: Every node has at most children. Every non-leaf node (except for the root) has at least children. The root has at least two children if it is not a leaf node. A non-leaf node with children contains keys. All leaves appear in the same level Each internal node’s keys act as a separation value which divides its subtrees.

The number of branches from a node is one more than the number of keys stored in that node. A B-tree is kept balanced by requiring that all leaf-nodes are at the same depth. More formally a B-tree of order is defined as a tree which satisfies the following properties: Every node has at most children. Every non-leaf node (except for the root) has at least children. The root has at least two children if it is not a leaf node. A non-leaf node with children contains keys. All leaves appear in the same level Each internal node’s keys act as a separation value which divides its subtrees.

The right child of a node can be used as forward pointer of the double linked list and the left child as backward pointer. A special case happens at the beginning, when the tail pointer of the double linked list is not defined as detailed in the code. root) return; if (root->left) bstToDoubleList(root->left, head, tail); root->left = *tail; if (*tail) (*tail)->right = root; else *head = root; *tail = root; if (root->right) bstToDoubleList(root->right, head, tail); }; Complexity Time complexity is) , where is the number of nodes in the list.

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